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Budhan covers a distance of 19 km in 2 hours by cycling one fourth of the time and walking the rest.The next day he cycles(at the same speed a before) for half the time and walks the rest(at the same speed as before) and covers 26 km in 2 hours. The speed in which budan walks is |
| Answer» ED in which budan walks is 6 km/hrExplanation : LET the speed of cycling = x km/hrspeed of walking = y km/hrcase-Itime of cycling = 2/4 = 0.5 HR=> distance covered by cycling = 0.5xtime of walking = 2 - 0.5 = 1.5 hr=> distance covered by walking = 1.5yhence0.5x + 1.5y = 19............eq1case-IItime of cycling = 2/2 = 1 hr=> distance covered by cycling = 1 *x = xtime of walking = 2 - 1 = 1 hr=> distance covered by walking = 1*y = yhencex + y = 26............eq2solving both eq1 and eq2 we getx = 20 km/hry = 6 km/hrHence the speed in which budan walks is 6 km/hr | |