Br−CH=CH−CH2−CH=CH−CH2−CH=C=C=CH−CH=C(CH3)2 Total number o – InterviewSolution

1.	Br−CH=CH−CH2−CH=CH−CH2−CH=C=C=CH−CH=C(CH3)2 Total number of geometrical isomers for the given compound is:
Answer» $B r - C H = C H - C H_{2} - C H = C H - C H_{2} - C H = C = C = C H - C H = C (C H_{3})_{2}$ Total number of geometrical isomers for the given compound is:

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