Bottles containing C_(6)H_(5)I and C_(6)H_(5)CH_(2)I lost their original labels. They were labelled A and B for testing. A and B were separately taken in test tubes and boiled with NaOH solution. The end solution in each tube was made acidic with dilute HNO_(3) and then some AgNO_(3) solution was added. Substance B gave a yellow precipitate. Which one of the following statements is true for this experiment?

Bottles containing C_(6)H_(5)I and C_(6)H_(5)CH_(2)I lost their origin

1.	Bottles containing C_(6)H_(5)I and C_(6)H_(5)CH_(2)I lost their original labels. They were labelled A and B for testing. A and B were separately taken in test tubes and boiled with NaOH solution. The end solution in each tube was made acidic with dilute HNO_(3) and then some AgNO_(3) solution was added. Substance B gave a yellow precipitate. Which one of the following statements is true for this experiment?
Answer» `A and C_(6)H_(5)CH_(2)I` `B and C_(6)H_(5)I` Addition of `HNO_(3)`was unneccessary A was `C_(6)H_(5)I` Solution :`C_(6)H_(5)Ioverset(NaOH)(to)C_(6)H_(5)ONaoverset(HNO_(3)"/"H^(+))(to)C_(6)H_(5)OHoverset(AgNO_(3))(to)` No yellow PPT. `C_(6)H_(5)CH_(2)Ioverset(NaOH)(to)C_(6)H_(5)CH_(2)ONaoverset(HNO_(3)"/"H^(+))(to)C_(6)H_(5)CH_(2)OHoverset(AgNO_(3))(to)` yellow ppt. Since benzyl iodide GIVES yellow ppt. hence this is COMPOUNDS B and A was phenyliodide `(C_(6)H_(5)I)`