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Both the end digits of a 99 digitnumber N are 2. N is divisibleby 11, then all the middle digitsare |
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Answer» We know, a number is only divisible by 11 if the difference between its sum of odd digits and even digits is 0 or 11.Here 99 digits is a odd number. So we will assume a number whose digits count is odd. for example: 2xxx2Let x=1 > 21112 => 2+1+2-1+1 = 3x=2 > 22222 = 2+2+2-2+2 = 2x=3 > 23332 = 2+3+2-3+3 = 1x=4 > 24442 = 2+4+2-4+4 = 0Therefore, 4 is the answer |
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