1.

Both points..class 10th trigonometry ​

Answer»

GIVEN:-

Here, we have️

ABC a right angled TRIANGLE

Right - angled at B

AB = 24cm

BC = 7cm

To Find :-

(i)sin A , cos A

(II) sin C , cos C

Solution :-

In ️ABC ,By Pythagoras theorem

AC² = AB² + BC²

AC² = 24² + 7²

AC² = 576 + 49

AC² = 625

AC=\sqrt{625}

Here, we have hypotenuse (AC) = 25

Therefore,

(i)

sin A = \frac{p}{h} = \frac{7}{25}

cos A = \frac{b}{h} = \frac{24}{25}

(ii)

sin C = \frac{p}{h} = \frac{24}{25}

cos C =\frac{b}{h} = \frac{7}{25}

And we are all done....!!


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