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Borazine (B3N3H6) hydrolyses slowly according to following reaction: B3N3H6 + H2O(excess)= NH3 + H3BO3 + H2. Weight of borazine required to form 0.2 mol H3BO3 is

Answer» Borazine (B3N3H6) hydrolyses slowly according to following reaction: B3N3H6 + H2O(excess)= NH3 + H3BO3 + H2. Weight of borazine required to form 0.2 mol H3BO3 is


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