1.

Bond energies of N-=N, H-H and N-H bonds are 945,463 & 391 kJ mol^(-1) respectively, the enthalpy of the following reactions is : N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)

Answer»


SOLUTION :`DELTAH = 6xxDeltaH_(N-H) - DeltaH_(N-N) - 3DeltaH_(H-H) = 93 KJ`


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