Bond dissociation energies of hydrogen and nitrogen are 430 kJ and 41.

1.	Bond dissociation energies of hydrogen and nitrogen are 430 kJ and 41.8 kJ respectively and the enthalpy of formation of NH is – 46 kJ. What is the bond energy of N-H bond?
Answer» 3H₂ + N₂ → 2NH₃; AH = -46 kJ 3 × ½H₂ + ½N₂ → 2 × ½NH₃ [(3× ½ × 430) + (½ × 941 .8)] – (3N-H) = – 46 [(3 × 215) + (470.9) + (46)] → [3N-H] [645 + 470.9 + 46] = 3N-H N-H = 387.3 kJ

Bond dissociation energies of hydrogen and nitrogen are 430 kJ and 41.8 kJ respectively and the enthalpy of formation of NH is – 46 kJ. What is the bond energy of N-H bond?

Answer»

3H₂ + N₂ → 2NH₃; AH = -46 kJ

3 × ½H₂ + ½N₂ → 2 × ½NH₃

[(3× ½ × 430) + (½ × 941 .8)] – (3N-H) = – 46

[(3 × 215) + (470.9) + (46)] → [3N-H]

[645 + 470.9 + 46] = 3N-H

N-H = 387.3 kJ

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Bond dissociation energies of hydrogen and nitrogen are 430 kJ and 41.8 kJ respectively and the enthalpy of formation of NH is – 46 kJ. What is the bond energy of N-H bond?

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