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Boiling point of water at 750mm Hg is 99.63^@C How much sucrose is to be added to 500g of water such that it boils at 100^@C K_b(water)= 0.52K kg mol^(-1)

Answer»

Solution :ELEVATION of boiling point,`Delta T_b =100-99.63 = 0.37^@`
`K_b` of water = 0.5 K kg`MOL^(-1)`
Molar MASS of sucrose `C_12H_22O_11= 342g mol^(-1)`
`Delta T_b = (1000K_bW_2)/(M_2W_1)`
`thereforeW_2` (mass of SOLUTE)=`(Delta T_b M_2 W_1)/(1000K_b)= (0.37xx342xx500)/(1000K_b)`=121.67g


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