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Boiling point of an aqueous solution is 100.1^(@)C. Latent heat of fusion and latent heat of vaporisation of water are "80 cal g"^(-1) and "540 cal g"^(-1) respectively. Calculate the freezing point of the solution. |
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Answer» Solution :`DeltaT_(b)=K_(b)xxm` `DeltaT_(F)=K_(f)xxm` `therefore""(DeltaT_(b))/(DeltaT_(f))=(K_(b))/(K_(f))` `"Putting"K_(b)=(RT_(B)^(2))/(1000l_(v))"and"K_(f)=(RT_(f)^(2))/(1000l_(f))` `(DeltaT_(b))/(DeltaT_(f))=(T_(b)^(2)xxl_(f))/(T_(f)xxl_(v))"or"(0.1)/(DeltaT_(f))=((100+273)^(2)xx80)/((0+273)^(2)xx540)"or"DeltaT_(f)=0.362^(@)` `therefore""T_(f)=0-0.362^(@)C=0.362^(@)C` |
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