Boiling point of a solvent is 80.2^(@)C. When 0.419g of the solute of – InterviewSolution

1.	Boiling point of a solvent is 80.2^(@)C. When 0.419g of the solute of molar mass 252.4 g mol- is dissolved im 75 g of the above solvent, the boiling point of the solution is found to be 80.256^(@)C. Find the molal elevation constant.
Answer» ANSWER :`K_(B)=2.53Kg"MOL"^(-1)`

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