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Block `B` of mass `2 kg` is placed on smooth horizontal plane. Block `A` to mass `1 kg` is placed on block `B`. The coefficient of friction between `A` and `B` is `0.40`. The block `A` is imparted a velocity `16 m//s` "at" `t=0`. Find the time at which momentum of the twoblocks are equal ( in seconds). `(g=10m//s^(2))` |
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Answer» Correct Answer - 2 `P_(1)=m_(1)V_(1)=(1) (16-mu"gt")` till velocities are equal. `P_(2)=m_(2)V_(2)=(2)((mum_(1)g)/(m_(2)))t=mu(1)"gt"`till velocities are equal. For `P_(1)=P_(2), 16-mu"gt"=mu"gt"` `t=(16)/((2)(0.4)(10))=2sec` |
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