1.

Block A has a mass of 5kg and is placed on the top ofsmooth triangular block Bhaving a mass of 25kg. If thesystem is released from rest,determine the distance Bmoves, in metre, when Areaches the bottom. Neglectthe size of block A.​

Answer»

hat,Mass of block A = 5 kgMass of block B = 25 KgSuppose the BASE is 0.5 MIF the system is at rest then the center of mass will be zero.When block A reaches the BOTTOM then block A moves in negative direction and block B moves in positive direction.So, the total distance covered by block A and B is   ....(I)We need to calculate the distance of BUsing formula of center of massPut the value of from equation (II) in equation (I)Put the value of both massesHence, The block of B moves 0.083 m.



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