1.

Black solid underset(Delta)overset(KOH+Air)to underset(("green"))((A))overset(H_(2)SO_(4))to underset(("purple"))((B))+(C) (i) KI on reaction with alkali solution of (B) changes into a compound (D). (ii) The colour of the compound (B) disappears on treatment with the acidic solution of FeSO_(4) (iii) With cold conc. H_(2)SO_(4) compound (B) gives (E), which being explosive decomposes to yield (F) and oxygen. ltBrgt Q. Which of the following options is correct?

Answer»

(C) and (F) are same compounds having same colour.
(C) and (F) are DIFFERENT compounds having same colour.
Compound (B) forms similar compound (E) with hot and conc.` H_(2)SO_(4)`.
Compound (A) does not give same TYPE of REACTION in acidic and neutral medium

Solution :`underset("Black solid")(2MnO_(2))+4KOH+O_(2) to underset("green (A)")(2K_(2)MnO_(4))+2H_(2)O`
`3MnO_(4)^(2-)+4H^(+) to underset((B))(2MnO_(4)^(-)+underset("(C) purple")(MnO_(2))+2H_(2)O)`
(i) `2KMnO_(4)+H_(2)O+KI to 2KOH +2MnO_(2)+underset((D))(KIO_(3))`
(ii) `2KMnO_(4)+8H_(2)SO_(4)+10FeSO_(4) to 2MnSO_(4)+5Fe_(2)(SO_(4))_(3)+K_(2)SO_(4)+8H_(2)O`
(iii) `2KMnO_(4)+H_(2)SO_(4) overset("cold")to underset((E))(Mn_(2)O_(7))+K_(2)SO_(4)+H_(2)O`
`underset((E))(Mn_(2)O_(7)) to underset((F))(2MnO_(2))+(3)/(2)O_(2)`
`6KMnO_(4)+10FeC_(2)O_(4)+24H_(2)SO_(4) to 6MnSO_(4) +underset(("YELLOW"))(5Fe_(2)(SO_(4))_(3))+20CO_(3)+3K_(2)SO_(4)+24H_(2)O`
`3NaSCN+FeCl_(3) to underset("Blood red colouration")(Fe(SCN)_(3)darr)+3NaCl`


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