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betweena and12. Find the value of k for which the points A (7, -2), B(5, 1) and C(3, k) are collinear. [2)hat ratio is the line segment joining the points P (-2 ¡3) and |
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Answer» For collinear points, area of triangle=0(1/2)[7(1-k)+5(k+2)+3(-2-1)]=0(1/2)[7-7k+5k+10-9]=0(1/2)[8-2k]=02k=8k=4 |
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