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Benzene (C_(6)H_(6)) and toluene (C_(7)H_(8)) from a nearly ideal solution at 313 K. The vapour pressure of pure benzene and toluene are 160 mm of Hg and 60 mm of Hg respectively. Calculate the partial pressure of benzene and toluene and the total pressure over the following solutions : (i) containing equal weights of benzene and toluene. |
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Answer» Molar mass of benzene, `C_(6)H_(6)="78 g mol"^(-1)," Molar mass of toluene, "C_(7)H_(8)="92 g mol"^(-1)` `therefore"Moles of benzene "=(w)/(78)" and Moles of toluene "=(w)/(92)` `"Total no. of moles in the solution "=(w)/(78)+(w)/(92)=(92w+78w)/(78xx92)=(170w)/(78xx92)` `therefore"Moles FRACTION of benzene,"x_(B)=(w//78)/(170w//(78xx92))=(92)/(170)=0.541` `"and MOLE fraction of toluene, "x_(T)=1-0.541 = 0.459` |
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