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Benzene burns according to the following equation 2C_(6)H_(6)(l)+15 O_(2)(g) rarr 12 CO_(2) (g)+6H_(2)O(l)""DeltaH^(@)= -6542 KJ What is the DeltaE^(@) for the combustion of 1.5 mol of benzene |
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Answer» `-3271 KJ` `DeltaH^(@)=DeltaE^(@)+(Deltan_(G))RT` `rArr ""-6542=DeltaE^(@)+(-3)(8.31)(298)xx10^(-3)""rArr""DeltaE^(@)=-6534 kJ` |
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