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Benzene and toluene from nearly ideal solutions. If at 300k, p_("toluene")^(0)=32.06 mm and p_("benzene")^(0)=103.01mm (a) Calculate the vapour pressure of a solution containing 0.6 molefraction of toluene (b) Calculate the mole fraction of toluene in the vapour for this composition of liquid |
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Answer» SOLUTION :(a) We have, `p=x_(A)*x_(A)^(0)+x_(B)*p_(B)^(0)`……………..(Eqn.3) Given that `x_("toluene")=0.6`, `x_("BENZENE")=1-0.6=0.4` `:.p=0.6xx32.06+0.4xx103.01` `=60.44mm` Again we have, `(1)/(p)=(x_(A).)/(p_(A)^(0))+(x_(B)^(.))/(p_(B)^(0))`...........(Eqn.5) `(1)/(60.44)=(x_("toluene")^(.))(32.06)+(x_("benzene").)/(103.01)` But `x_("toluene").+x_("benzene").=1` `:. (1)/(60.44)=(x_("toluene").)/(32.06)+(1-x_("toluene").)/(103.01)` `:.x_("toluene").=0.3182` |
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