\begin { equation } \sqrt{\sec ^{2} \theta+\csc ^{2} \theta}=\tan \the – InterviewSolution

1.

\begin { equation } \sqrt{\sec ^{2} \theta+\csc ^{2} \theta}=\tan \theta+\cot \theta \end { equation }

Answer»

As sin²theta+ cos²theta= 1sectheta=1/costheta

RHS

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