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\begin { equation } \operatorname{lt}_{x \rightarrow \frac{\pi}{2}}\left(\frac{\pi}{2}-x\right) \tan x \end { equation } |
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Answer» lim x->pie/2 (pie/2 - x)*tanx = lim x->pie/2 (pie/2 - x)/cotx if we pit x=pie/2 we will get 0/0 form so using L'hospital rule (pie/2 - x) (-1)/(-cosecx*cosecx) = (-1)/(-1) = 1 |
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