\begin { equation } (4-d)^{3}+(4)^{3}+(4+d)^{3}=288 \end { equation } – InterviewSolution

1.	\begin { equation } (4-d)^{3}+(4)^{3}+(4+d)^{3}=288 \end { equation }
Answer» (4-d)³ + 4³ + (4+d)³ = 2884³-d³-12d(4-d) + 4³ + 4³+d³+12d(4+d) = 2883× 4³ + 12d² + 12d² = 28824d² = 288 - 19224d² = 96d² = 4d = √(4)d = 2 or - 2

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