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\begin{array} { l } { \text { If } x = r \sin A \cos C , y = r \sin A \sin C \text { and } z = r \cos A } \\ { \text { then prove that } x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = r ^ { 2 } } \end{array} |
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Answer» Given, x=rsinAcosC ..equation..1 y=rsinAsinC .....equation 2 z=rcosA .....equation 3 squaring and adding all three equations we get the following x²+y²+z²=r²(sin2Acos2C + sin2Asin2C + cos2A) =r²{sin2A(cos2C + sin2C) + cos2A} =r²{sin2A+ cos2A} ∴x²+y²+z²=r² |
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