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\begin{array}{l}{\text { If } \frac{a x+b y}{x+y}=\frac{b x+a z}{x+z}-\frac{a y+b z}{y+z} \text { and } x+y+z \neq 0} \\ {\text { then prove that each ratio is } \frac{a+b}{2}}\end{array} |
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Answer» lets take x=y=z=1so x+y+z=3!=0so (ax+by)/(x+y)=(a+b)/2so (bx+az)/(x+z)=(a+b)/2so (ay+bz)/(y+z)=(a+b)/2Hence Proved |
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