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\begin{array} { l } { \text { Given that } \log _ { 5 } x - \log _ { 3 } ( x - 5 ) = \log _ { 3 } A , \text { express } A \text { in terms of } x . } \\ { \text { hence or otherwise, solve the equation } \log _ { 3 } x - \log _ { 3 } ( x - 5 ) = 1 } \end{array} |
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Answer» Thank u but can u pls solve question b too pls |
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