\begin{array}{l}{\frac{1}{(3 x+y)}+\frac{1}{(3 x-y)}=\frac{3}{4}} \\ { – InterviewSolution

1.	\begin{array}{l}{\frac{1}{(3 x+y)}+\frac{1}{(3 x-y)}=\frac{3}{4}} \\ {\frac{1}{2(3 x+y)}-\frac{1}{2(3 x-y)}=\frac{-1}{8}}\end{array}
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