1.

Based onthe following thermochemical equations H_(2)O(g)+C(s)rarrCO(g)+H_(2)(g), DeltaH=131 kJCO(g)+(1)/(2)O_(2)(g)rarrCO_(2)(g),DeltaH=-282 kJC(s) +O_(2)(g)rarrCO_(2)(g),DeltaH=X kJThe value of X is

Answer»

`-393 KJ`
`-655 kJ`
`+393 kJ`
`+655 kJ`

Solution :eq. (i) + eq. (II) + eq. (III) gives
X=131-282-242=-393 kJ.


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