1.

Based on the values of bond energies (B.E.) given, ΔfH∘ of N2H4(g) is:Given : N−N=159 kJ mol−1; H−H=436 kJ mol−1N≡N=941 kJ mol−1; N−H=398 kJ mol−1

Answer»

Based on the values of bond energies (B.E.) given, ΔfH∘ of N2H4(g) is:

Given : N−N=159 kJ mol−1; H−H=436 kJ mol−1N≡N=941 kJ mol−1; N−H=398 kJ mol−1


Discussion

No Comment Found

Related InterviewSolutions