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Based on the data given below , the correct order of reducing power is : Fe^(3+)(aq) +erarrFe^(2+)(aq),E^@=+0.77V AI^(3+)(aq)+3erarrAI(s),E^@=-1.66V Br_2(aq) +2e rarr2Br^-(aq),E^@ =+1.08V |
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Answer» `Br^- LT Fe^(2+) lt AI` |
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