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Based on solute-solvent interactions, arrange the following in order of increasing sobulity in n-otane and explain. Cyclohexane, KCl, CH_(3)OH, CH_(3)CN |
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Answer» Solution :(i) Cyclohexane and n-octane both are non-polar. Hence, they mix completely in all proportions. (II) KCL is an ionic compound while n-octane is non-polar. Hence, KCl will no dissolve at all in n-octane. (iii) `CH_(3)OH and CH_(3)CN`both are polar but `CH_(3)CN` is less polar than `CH_(3)OH`. As the SOLVENT is non-polar, `CH_(3)CN` will dissolve more than `CH_(3)OH` in n-octane. THUS, the order of solubility will be `KCl lt CH_(3)OH lt CH_(3)CN lt "Cyclohexane."` |
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