Based on data given below, match column-I and column II 3X(g)overset("250K,1atm")toX_3(g), DeltaH=-200 KJ//mol , DeltaS=-300 J//K//mol X(l)overset("1atm,250K")toX(g), DeltaH_(vap)=10 KJ//mol X_3(l)overset("500K,1atm")toX_3(g), DeltaH_(vap)=80 KJ//mol X_3(g,250 K , 1 atm )toX_3(g, 500 K, 1 atm) DeltaH=100KJ/mol,DeltaS=100 J/K/mol , DeltaG=60 KJ/mol Normal boiling point of X=250 K normal boiling point of X_3=500 K. Enthalpy change and entropy change of cooling X_3(l) to lower temperature is neglible.

Based on data given below, match column-I and column II 3X(g)overset(

1.	Based on data given below, match column-I and column II 3X(g)overset("250K,1atm")toX_3(g), DeltaH=-200 KJ//mol , DeltaS=-300 J//K//mol X(l)overset("1atm,250K")toX(g), DeltaH_(vap)=10 KJ//mol X_3(l)overset("500K,1atm")toX_3(g), DeltaH_(vap)=80 KJ//mol X_3(g,250 K , 1 atm )toX_3(g, 500 K, 1 atm) DeltaH=100KJ/mol,DeltaS=100 J/K/mol , DeltaG=60 KJ/mol Normal boiling point of X=250 K normal boiling point of X_3=500 K. Enthalpy change and entropy change of cooling X_3(l) to lower temperature is neglible.
Answer» SOLUTION : OVERALL `DeltaH=3xx10-200+100-80+0=300-200+100-80=-150` kJ/mol `DeltaS=20-300+100-160+0=-240` J/mol/K `DeltaG=0+(-125)+60+0+0=-65` kJ/mol