Saved Bookmarks
| 1. |
Ball `1` is released from the top of a smooth inclined plane, the at the same instant ball `2` is projected from the foot of the plance with such a velocity that they meet halfway up the incline. Determine: a.the velocity with which balls are projected and b. the velocity of each ball when they meet. . |
|
Answer» For ball 1: `u_(1)=0, a=g sun theta=g ((h)/(l))` and `s=l//2` Using `v^(2)=u^(2)+2as rArr v^(2)=0+2g ((h)/(l)).((1)/(2))` `rArr v=sqrtgh` Again using `v=u+at rArr v=0+g ((h)/(l)).t` `sqrtgh=g ((h)/(l))t rArr t=(l)/(sqrtgh)` For nall 2: `u=u_(2), v=v_(2)` and `a=-g sin theta=-((h)/(l))` Using `v^(2)=u^(2)2as rArr v_(2)^(2)=u_(2)^(2)+2(-g(h)/(l)).((l)/(2))` ...(iii) Asing using `v=u+at rArr v_(2)=u_(2)-(g(h)/(l)).(l)/(sqrtgh)` ...(iv) Form (iii) and (iv) `u_(2)=sqrtgh and v_(2)=0` Hence velocity of ball `2` at the of throwing will be and when it meets ball `1` its velocity becomes zero. The velocity of ball `1` when it meets ball `2` is `sqrtgh`. |
|