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Balance the following skeleton equation : Mg_(3)N_(2)+H_(2)OrarrMg(OH)_(2)+NH_(3). |
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Answer» Solution :The biggest formula is `Mg_(3)N_(2)`. Hence, the various atoms are balanced in the order : Mg, N and H. (i) to equalise the number of Mg atoms on both sides, MULTIPLY Mg `(OH)_(2)` by 3. We get `Mg_(3)N_(2)+H_(2)Orarr 3Mg (OH)_(2)+NH_(3)` (ii) To balance the nitrogen atoms, multiply `NH_(3)` by 2 on the R.H.S. We get `Mg_(3)N_(2)+H_(2)Orarr 3Mg (OH)_(2)+2NH_(3)` (iii) to equalise the number of H and O atoms on both side of the above equation, multiply `H_(2)O` OCCURRING on L.H.S. of the equation by 6. We get `Mg_(3)N_(2)+6H_(2)Orarr 3Mg(OH)_(2)+2NH_(3)` This is the required balanced chemical equation. |
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