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Balance the following skeleton equation by the method of Partial Equations : KMnO_(4)+H_(2)SO_(4)+(COOH)_(2) rarr K_(2)SO_(4)+MnSO_(4)+CO_(2)+H_(2)O. |
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Answer» Solution :The oxidation of oxalic ACID, `(COOH)_(2)`, by potassium permaganate, `KMnO_(4)`, takes place in the FOLLOWING steps : (i) `KMnO_(4)` reacts with dil. `H_(2)SO_(4)` to produce nascent oxygen. `KMnO_(4)+H_(2)SO_(4)rarr K_(2)SO_(4)+MnSO_(4)+H_(2)O+(O)` By balancing this skeleton equation by Hit and Trial method, we ge `2KMnO_(4)+3H_(2)SO_(4) rarr K_(2)SO_(4)+2MnSO_(4)+3H_(2)O+5(O)"...(1)"` (ii) Oxalic acid is oxidised to `CO_(2)` and `H_(2)O` by the nascent oxygen produced in equation (1). The balanced partial equation for this reaction is : `(COOH)_(2)+(O)rarr 2CO_(2)+H_(2)O"...(2)"` To cancel the intermediate product, i.e., nascent oxygen, MULTIPLY equaiton (2) by 5 and ADDING to (1), we have `2KMnO_(4)+3H_(2)SO_(4)+5(COOH)_(2)rarr K_(2)SO_(4)+2MnSO_(4)+10CO_(2)+8H_(2)O` This represents the balanced chemical equation for the above reaction. |
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