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Balance the following reactions by ion electron method : KMnO_(4) + H_(2) SO_(4) + HCl rarr K_(2) SO_(4) + MnSO_(4) + Cl + H_(2) O |
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Answer» SOLUTION :Ionic FORM of the given reactionis Step I `:` Ionic form of the given reaction is or `MnO_(4) + H^(+) + Cl^(-) rarr Mn^(2-) + Cl_(2) + H_(2) O` Step II `:` Oxidation `Cl^(-) rarr overset( 0 ) ( C) l_(2)` REDUCTION `:``overset( + 7)(M) n O_(4)^(-) rarr Mn^(2+)` Step II `:` Oxidation `Cl^(-) rarr overset( 0 ) ( C) l_(2)` Reduction`: overset( +7)(M) nO_(4)^(-) rarr Mn^(2+)` Step III `:` Oxidation `2Cl^(-) rarr Cl_(2)` Reduction `: MnO_(4)^(-)rarr Mn^(2+)` Step IV ` :`Oxidation `2Cl^(-) rarrCl_(2)` Reduction `: MnO_(4)^(-) + 8 H^(+) rarr Mn^(2+)+ 4H_(2) O ` Step V `: ` Oxidation `2Cl^(-) rarr Cl_(2) + 2e` Reduction `MnO_(4) ^(_) + 8 H^(+) + 5e rarr Mn^(2+) + 4H_(2) O` Step VI` :` Oxidation `2Cl^(-) rarr Cl_(2) + 2e ]xx 5 ` Reduction `: MnO_(4)^(-) + 8 H^(+) +5e rarr Mn^(2+) + 4H_(2) O ] xx 2 ` Step VII `: 2KMnO_(4) + 10 HCl + 3H_(2) SO_(4) rarr 2MnSO_(4) + 8 H_(2)O + 5Cl_(2) + K_(2) SO(4)`is the balanced reaction. |
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