B11TI3I32211Area of the rectangle= 12 cm x 2 cm = 24 sq cmArea of the

1.	B11TI3I32211Area of the rectangle= 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cmArea of rectangle III3 cm x 1 cm =3 sq cm- Total area of the given figure = 3 sq cm + 3sq cm + 3 sq cm = 9 sq cm.
Answer» ANSWER: HI there I am ALSO not in any WAY I

B11TI3I32211Area of the rectangle= 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cmArea of rectangle III3 cm x 1 cm =3 sq cm- Total area of the given figure = 3 sq cm + 3sq cm + 3 sq cm = 9 sq cm.

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ANSWER:

HI there I am ALSO not in any WAY I

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B11TI3I32211Area of the rectangle= 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cmArea of rectangle III3 cm x 1 cm =3 sq cm- Total area of the given figure = 3 sq cm + 3sq cm + 3 sq cm = 9 sq cm.​

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B11TI3I32211Area of the rectangle= 12 cm x 2 cm = 24 sq cmArea of the rectangle Il= 8 cm x 2 cm = 16 sq cmArea of rectangle III3 cm x 1 cm =3 sq cm- Total area of the given figure = 3 sq cm + 3sq cm + 3 sq cm = 9 sq cm.