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(b) What volume of 0.6 M sodium formate solution is required to prepare a buffer solution is required to prepare a buffer solution of pH 4.0 by mixing it with 100 ml of 0.8 M formic acid . (Given pK_(a)for formic acid is 3.75). |
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Answer» SOLUTION :(b) `pH=pK_(a)+LOG (["salt"])/(["acid")]` `4=3.75+log. (["Sodium FORMATE"])/(["formic acid"])` [ Sodium formate] = NUMBER of MOLES of `HCOONa` `=0.6xxVxx10^(-3)` `=80xx10^(-3)` `4=3.75+log.(0.6V)/(80)` `0.25 = log.(0.6V)/(80)` antilog of `0.25=0.6 V` `0.6V-1.778xx80` `=1.78xx80` `=142.4` `V=(142.4 mL )/(0.6)=237.33 mL ` |
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