1.

(b) The E^(theta) values corresponding to the following two reduction electrode processes are : (i) Cu^(+)//Cu=0.52V"(ii) Cu^(2+)//Cu^(+)=0.16V Formulate the galvanic cell for their combination. Calculate the cell potential and DeltaG^(@) for the cell reaction.

Answer»

SOLUTION :`Cu^(2+)+e^(-)rarrCu`
`Cu^(+)RARR Cu^(2+)+e^(-)`
`"OVERALL cell reaction :"2Cu^(+)rarrCu+Cu^(2+)`
`Cu^(+)//Cu^(2+)||Cu^(+)//Cu`
`E_("cell")^(theta)=0.52-0.16=0.36V`
`DELTAG^(@)=-mFE_("cell")^(theta)`
`=-1xx96500xx0.36`
`=-"24740 J MOL"^(-1)`


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