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(b) Suggest a way to determine the Lambda_(m)^(@)" for "CH_(3)COOH. |
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Answer» Solution :`Lambda^(@)CH_(3)COOH=?` `Lambda^(@)CH_(3)COO^(-)+Lambda^(@)H^(+)=Lambda^(@)NA^(+)+Lambda^(@)H^(+)+Lambda^(@)Cl^(-)-Lambda^(@)Na^(+)-Lambda^(@)Cl^(-)"….(i)"` `Lambda_(m)^(@)CH_(3)COOH=Lambda^(@)CH_(3)COONa+Lambda^(@)HCl-Lambda^(@)NaCl` |
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