Saved Bookmarks
| 1. |
b on the coordinate axes.Find the equation of a circle with centre (2. 2) and passes through the point (4, 5).Does the point (-2.5, 3.5) lie inside, outside or on the circle xy25? |
|
Answer» Concept :- If (a, b) is the point on the circle and (h,k) is the centre of circle, then radius (r) = √{(a-h)² + (b-k)²}. Then use equation of circle is ( x - h)² + (y - k)² = r² Here, centre = (2, 2) and point on the circle is (4, 5) Then, radius (r) = √{(4-2)² +(5-2)²} r = √13 Now, equation of circle is (x - h)² + (y - k)² = r²(x - 2)² + (y - 2)² = √13²x² + 4 - 4x + y² + 4 - 4y = 13 x² + y² - 4x - 4y -5 = 0 Hence, equation of circle is x² + y² - 4x - 4y -5 = 0 Like my answer if you find it useful! |
|