1.

B is twice as old as A today. In 10 years, the ratio of ages of A and B will be 2 : 3. Find the present age of B.1. 12 years2. 10 years3. 20 years4. 15 years

Answer» Correct Answer - Option 3 : 20 years

Given:

B is twice as old as A today

In 10 years, the ratio of ages of A and B will be 2 : 3

Calculation:

B is twice as old as A today

⇒ B = 2A

⇒ B/A = 2/1

Let the present age of A be ‘x’

⇒ B = 2x, A = x

In 10 years ratio of A : B becomes 2 : 3

⇒ (x + 10)/(2x + 10) = 2/3

⇒ 3x + 30 = 4x + 20

⇒ x = 10

Age of B

⇒ 2 × 10

⇒ 20 years

∴ The present age of B is 20 years.


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