B. In the given figure DEIIBC then find AD.A2cm6cm,4cm

1.	B. In the given figure DEIIBC then find AD.A2cm6cm,4cm
Answer» Answer is 3Because AD/DB=AE/ECAD/6=2/4AD=12/4AD=3 By Basic Proportionality Theroem- AD/DB = AE/EC putting the values given in the fig. AD/6 = 2/4 by cross - multiplication, 4AD = 12 AD = 12/4 AD = 3 therefore, AD = 3 since DE//BCTherefore using Thale's theorem we getAD/DB=AE/ECAD/6=2/4AD=(2x6)/4AD=3cm is the correct answer 3 Is the correct answer of the given question let AD=XBY THELES THEOREMSAD/AB= AE/ACX/X+6= 2/66X= 2X+126X-2X= 124X= 12X= 12/4=3cmAD= 3cm By Using Thales Theoram, AD AE x 2------ = ------ => ------ = ------ AB AC x+6 6 => 6 ( x ) = 2 ( x+6 )=> 6x - 2x = 12=> 4x = 12 12=> x = ------ = 3cm 4 AD/DB=AE/EC (By B. P. T) AD/6=2/4 ( cross multiply)4AD=12AD=12/4=3then AD=3

Answer»

Answer is 3Because AD/DB=AE/ECAD/6=2/4AD=12/4AD=3

By Basic Proportionality Theroem-

AD/DB = AE/EC

putting the values given in the fig.

AD/6 = 2/4

by cross - multiplication,

4AD = 12 AD = 12/4 AD = 3

therefore, AD = 3

since DE//BCTherefore using Thale's theorem we getAD/DB=AE/ECAD/6=2/4AD=(2x6)/4AD=3cm is the correct answer

3 Is the correct answer of the given question

let AD=XBY THELES THEOREMSAD/AB= AE/ACX/X+6= 2/66X= 2X+126X-2X= 124X= 12X= 12/4=3cmAD= 3cm

By Using Thales Theoram,

AD AE x 2------ = ------ => ------ = ------ AB AC x+6 6

=> 6 ( x ) = 2 ( x+6 )=> 6x - 2x = 12=> 4x = 12

12=> x = ------ = 3cm 4

AD/DB=AE/EC (By B. P. T) AD/6=2/4 ( cross multiply)4AD=12AD=12/4=3then AD=3

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