1.

(b) (i) What happens when the following alkenes are subjected to reductive ozonolysis. 1. Propene, 2. Butene, 3. Isobutylene. (ii) What are reducing and non - reducing sugars?

Answer»

Solution :(i) 1. Propene: `underset("Propene")(CH_(3)-CH=CH_(2)) overset(O_(3)) underset(Zn//H_(2)O) to underset("Acetaldehyde")(CH_(3)CHO) + underset("Formaldehyde")(HCHO)`
2. 1- Butene: `CH_(3)-underset(1-"Butene") (CH_(2) -CH) = CH_(2) overset(O_(3)) underset(Zn//H_(2)O) to underset("Propanaldehyde")(CH_(3)-CH_(2)-CHO) + underset("Formaldehyde")(HCHO)`
3. ISOBUTYLENE: `underset("Isobutylene")(CH_(3)-underset(CH_(3))underset(|)C =CH_(2) overset(O_(3)) underset(Zn//H_(2)O) to underset("Acetone")(CH_(3)-underset(CH_(3))underset(|)C=O + underset("Formaldehyde")(HCHO)`
(ii) Reducing sugars: Those carbonhydrates which contain free aldehyde or ketonic group and reduces Fehling’s solution and TOLLEN’s reagent are called reducing sugars.All monosacchaides whether aldose or ketone are reducing sugars.
Non reducing agent: Cabohydrates which do not reduce Tollen’s reagent and Fehling’s solution are called non-reducing sugars. Example Sucrose. They do not have free aldehyde group.


Discussion

No Comment Found