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B) Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be MR2/4, find its moment of inertia about an axis normal to thedisc and passing through a point on its edge. |
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Answer» Moment of inertia of disc about its diameter is I d = 41 MR 2 MI of disc about a TANGENT passing through rim and in the plane of disc is I=I G +MR 2 = 41 MR 2 +MR 2 = 45 MR 2 |
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