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Answer» Let a be the First term, a3 be the third term, a5 be the 5th term and a7 be the 7th terma3 = 16a7 = a5 + 12 ............ (1)Let the common difference be "d"Common difference is equal in APSo,a7 = a5 + d + d = a5 + 2d............(2)From Equation (1) & (2)a5 + 12 = a5 + 2d2d = 12d = 6 From Given, we get that a3 = 16a3 = a + 2d = 16a + ( 2× 6 ) = 16 [ We know that d = 6 ]a + 12 = 16a = 4 So first term is 4 .... We can find AP by adding d continuouslySo,AP is 4, 10, 16, 22, 28....... |
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