1.

B.C. 35 m3. A battery whose e.m.f. is 40 V has an internal resistance of 5 . If this batterconnected to a 15 2 resistor 'R', what will be the voltage drop across 'R'?A. 10 VD. 50 VB. 30 VE. 70 Vr40 V​

Answer»

Answer:

Total Resistance = Internal resistance + external resistance

R=5+15

R=20 Ω

Total current flowing in the circuit

I= E/R

I= 40/20=2

I=2 Amps.

Drop Across 15Ω resistor

V= IR

V=2 x 15

V=30 Volts

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