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B.C. 35 m3. A battery whose e.m.f. is 40 V has an internal resistance of 5 . If this batterconnected to a 15 2 resistor 'R', what will be the voltage drop across 'R'?A. 10 VD. 50 VB. 30 VE. 70 Vr40 V |
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Answer» Answer: Total Resistance = Internal resistance + external resistanceR=5+15R=20 ΩTotal current flowing in the circuitI= E/RI= 40/20=2I=2 Amps.Drop Across 15Ω resistorV= IRV=2 x 15V=30 VoltsPLZ MARK AS BRAINLIEST ANSWER AND THX FOR THE SUPERB QUESTION
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