(b) At present, the sum of the ages of Ruby and her daughter is 49. Se

1.	(b) At present, the sum of the ages of Ruby and her daughter is 49. Seven years ago Ruby was sixtimes as old as her daughter. Findtheir present ages.
Answer» let age of ruby=xage of her daughter=ySEVEN YEARS AGOruby=x-7her daughter's age= y-7ruby age= 6(y-7)x-7=6(y-7) SUM OF THEIR AGES=49 ruby age + daughter age=496(y-7)+ (y-7)=496y - 42 + y -7=498y - 49-7=498y = 2×49y=98 / 8y=12 years 3 months

(b) At present, the sum of the ages of Ruby and her daughter is 49. Seven years ago Ruby was sixtimes as old as her daughter. Findtheir present ages.

Answer»

let

age of ruby=xage of her daughter=ySEVEN YEARS AGOruby=x-7her daughter's age= y-7ruby age= 6(y-7)x-7=6(y-7)

SUM OF THEIR AGES=49

ruby age + daughter age=496(y-7)+ (y-7)=496y - 42 + y -7=498y - 49-7=498y = 2×49y=98 / 8y=12 years 3 months