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b) An element crystallizes in a foc lattice. The edge length of the unit cell is 400 pm. Calculate the density of the unit cell. ("molar mass"="60 g mol"^(-1)) ("Avogadro number"=6.02 xx 10^(23)) |
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Answer» SOLUTION :`d=(zM)/(a^(3)N_(A))` `"Given, In FCC"` `Z=4, M="60 g MOL"^(-1), a="400 pm "=400xx10^(-10)cm^(3)` `d=("4 atomz "xx"60 g mole"^(-1))/((400xx10^(-10)cm)^(3)xx(6.023xx10^(23)" atoms mol"^(-1)))` `=6.226g cm^(-3)` |
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