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B. A force act for a 0.1s on a body of mass 1.2 Kg initially at rest. The force thenceases to act and the body moves through 2m in the next ls. Find the magnitudeof force. |
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Answer» Answer: u = 0m/s t = 0.1s s = 2m Now, s = UT + 1/2at² 2 = 1/2a(0.1)² 4 = 0.01a a = 400m/s² Now, m = 1.2kg F = ma F = 1.2 x 400 F = 480N Hope it HELPS you!! |
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