(b) a(C) 2d24. A triangle and parallelogram are constructed on the same base such that their areas are equal. If thealtitude of the parallelogram is 100 m, the altitude of the triangle is:(a) 10/2 m(c) 100/2 m(d) 200 m(b) 100 mf n tranerium measures 1440 m2. The perpendicular distance between

(b) a(C) 2d24. A triangle and parallelogram are constructed on the sam

1.	(b) a(C) 2d24. A triangle and parallelogram are constructed on the same base such that their areas are equal. If thealtitude of the parallelogram is 100 m, the altitude of the triangle is:(a) 10/2 m(c) 100/2 m(d) 200 m(b) 100 mf n tranerium measures 1440 m2. The perpendicular distance between
Answer» Let the triangle and parallelogram have common base b,let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), thenArea of triangle =12∗b∗h1Area of rectangle =b∗h2As per question12∗b∗h1=b∗h212∗b∗h1=b∗100h1=100∗2=200m