--ax2 +dx + c, where ac0, then P(x). Q(x)-0 has(x)=ax" + bx + c and Q(

1.	--ax2 +dx + c, where ac0, then P(x). Q(x)-0 has(x)=ax" + bx + c and Q(x)(A) exactly one real root(C) exactly three real rootsQ. IIf P(B) atleast two real roots(D) all four are real roots
Answer» For the first equation without loss of generality assume a>0 then since none of a and c is zero graph of P(x) will be -ve at -infinity and +ve at +inifinty so it will cut x axis at once atleast Same is the case with Q(x) So totally the P(x)Q(x)=0 will have atleast 2 real roots

--ax2 +dx + c, where ac0, then P(x). Q(x)-0 has(x)=ax" + bx + c and Q(x)(A) exactly one real root(C) exactly three real rootsQ. IIf P(B) atleast two real roots(D) all four are real roots

Answer»

For the first equation without loss of generality assume a>0

then since none of a and c is zero

graph of P(x) will be -ve at -infinity and +ve at +inifinty

so it will cut x axis at once atleast

Same is the case with Q(x)

So totally the P(x)Q(x)=0 will have atleast 2 real roots